班级________ 姓名________ 考号________ 日期________ 得分________
一、选择题:(本大题共6小题,每小题6分,共36分,将正确答案的代号填在题后的括号内.)
1.limn→∞ n1-131-141-15…1-1n+2等于( )
A.0 B.23
C.1 D.2
解析:limn→∞ n1-131-141-15…1-1n+2
=limn→∞ n•23 •34…•n+1n+2
=limn→∞ 2nn+2=limn→∞ 2n+2-4n+2=limn→∞ 2-4n+2=2
答案:D
2.limn→∞ 1+3+5+…+2n-1n2n+1=( )
A.14 B.12
C.1 D.2